Allegiant Air G46506 Flight Status Today

Domestic flight Allegiant Air G46506 takes off from Cleveland (CLE) United States to Savannah (SAV) United States. It's operated by Allegiant Air. The plane leaves Cleveland Hopkins International Airport at 16:00 America/New_York. The flight is expected to land at Savannah/Hilton Head Airport at 17:50 America/New_York. The flight will last about 2 hours 6 minutes.

G46506 - AAY6506 Allegiant Air (G4)
CLE Cleveland United States
Flight CLE to SAV
SAV Savannah United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 16-February-2021
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 16:00
None A3
Arrival Savannah/Hilton Head Airport
IATA: SAVICAO: KSAV
Scheduled 17:50
None 12
G46506 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 6 minutes
  • Flight Distance: 1031 kms / 641 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A319
  • Callsign: AAY6506
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Cleveland: Monday 2025-12-29 18:22 PM
  • Current Time in Savannah: Monday 2025-12-29 18:22 PM

Flight routes similar to Allegiant Air G46506

Airline Flight no Departure Arrival
United Airlines UA3237
United Airlines 		29/12/2025
19:00 		1 hours 58 minutes
20:40
Frontier Airlines F94127
Frontier Airlines 		29/12/2025
10:21 		1 hours 52 minutes
12:07

Allegiant Air Flight G46506 FAQs

What is the scheduled flight duration for Allegiant Air G46506 flight?

On average, nonstop flight takes 2 hour(s) 6 minutes, with the flight distance of 1031 km (641 miles).

What type of aircraft is used for the Allegiant Air G46506 flight?

All Allegiant Air G46506 flights are operated using Airbus A319 aircraft.