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Allegiant Air G4604 Flight Status Today
Domestic flight Allegiant Air G4604 takes off from Indianapolis (IND) United States to Jacksonville (JAX) United States. It's operated by Allegiant Air. The plane leaves Indianapolis International Airport at 06:00 America/Indiana/Indianapolis. The flight is expected to land at Jacksonville International Airport at 07:55 America/New_York. The flight will last about 1 hours 55 minutes.
- Type: Domestic Flight
- Flight Duration: 1 hours 55 minutes
- Flight Distance: 1106 kms / 687 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Monday, Sunday
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
- Aircraft: Airbus A320 (sharklets)
- Callsign: F-KLEX5
- Departure Timezone: America/Indiana/Indianapolis
- Arrival Timezone: America/New_York
- Current Time in Indianapolis: Saturday 2026-04-11 19:35 PM
- Current Time in Jacksonville: Saturday 2026-04-11 19:35 PM
Allegiant Air Flight G4604 FAQs
What is the scheduled flight duration for Allegiant Air G4604 flight?
On average, nonstop flight takes 1 hour(s) 55 minutes, with the flight distance of 1106 km (687 miles).
What type of aircraft is used for the Allegiant Air G4604 flight?
All Allegiant Air G4604 flights are operated using Airbus A320 (sharklets) aircraft.
How many Allegiant Air G4604 flights are operated a week?
2 flights per week. The Flight Allegiant Air G4604 is operated on Monday, Sunday.
