Allegiant Air G4604 Flight Status Today

Domestic flight Allegiant Air G4604 takes off from Indianapolis (IND) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Indianapolis International Airport at 06:00 America/Indiana/Indianapolis. The flight is expected to land at St. Petersburg-Clearwater International Airport at 08:18 America/New_York. The flight will last about 2 hours 10 minutes.

G4604 - AAY604 Allegiant Air (G4)
IND Indianapolis United States
Flight IND to PIE
PIE Saint Petersburg United States
Contact Airlines It may not operate on the date requested
Departure Indianapolis International Airport
IATA: INDICAO: KIND
Scheduled 06:00
None B4
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 08:18
None 10
G4604 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 10 minutes
  • Flight Distance: 1351 kms / 839 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Monday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: F-KLEX5
  • Departure Timezone: America/Indiana/Indianapolis
  • Arrival Timezone: America/New_York
  • Current Time in Indianapolis: Monday 2025-12-29 16:39 PM
  • Current Time in Saint Petersburg: Monday 2025-12-29 16:39 PM

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Allegiant Air Flight G4604 FAQs

What is the scheduled flight duration for Allegiant Air G4604 flight?

On average, nonstop flight takes 2 hour(s) 10 minutes, with the flight distance of 1351 km (839 miles).

What type of aircraft is used for the Allegiant Air G4604 flight?

All Allegiant Air G4604 flights are operated using Airbus A320 aircraft.

How many Allegiant Air G4604 flights are operated a week?

2 flights per week. The Flight Allegiant Air G4604 is operated on Monday, Sunday.