Check your Flight status online
Allegiant Air G43104 Flight Status from Oklahoma City to Fort Walton Beach, United States today
Domestic flight Allegiant Air G43104 from Oklahoma City (OKC) United States to Fort Walton Beach (VPS) United States operated by Allegiant Air. Scheduled time of departure from Will Rogers World Airport is 19:15 America/Chicago and scheduled time of arrival in Destin Fort Walton Beach Airport is 21:14 America/Chicago. The duration of the flight is 1 hours 54 minutes.
G43104 - AAY3104
Allegiant Air (G4)
OKC
Oklahoma City United States
VPS
Fort Walton Beach United States
Contact Airlines
It may not operate on the date requested
G43104 Detail
- Type: Domestic Flight
- Flight Duration: 1 hours 54 minutes
- Flight Distance: 1166 kms / 725 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Monday, Friday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Airbus A320
- Callsign: F-KMWA2
- Departure Timezone: America/Chicago
- Arrival Timezone: America/Chicago
- Current Time in Oklahoma City: Wednesday 2024-05-01 07:38 AM
- Current Time in Fort Walton Beach: Wednesday 2024-05-01 07:38 AM
Allegiant Air G43104 flight status on other days
Similar flight route from Oklahoma City (OKC) to Fort Walton Beach (VPS)
Airline | Flight no | Departure | Arrival |
---|---|---|---|
G46908 Allegiant Air |
01/05/2024 14:25 (-6:00) |
1 hours 36 minutes None (-6:00) |
Frequently asked questions, answered
How long is the flight from Oklahoma City to Fort Walton Beach?
On average, nonstop flight takes 1 hour(s) 54 minutes, with the flight distance of 1166 km (725 miles).
What type of aircraft is used for the Allegiant Air G43104 flight?
All Allegiant Air G43104 flights are operated using Airbus A320 aircraft.
How many Allegiant Air G43104 flights are operated a week?
2 flights per week. The Flight Allegiant Air G43104 is operated on Monday, Friday.