EZ Air 7Z9507 Flight Status : Live Tracking & Updates

Domestic flight EZ Air 7Z9507 takes off from Louisville (SDF) United States to Kansas City (MCI) United States. It's operated by EZ Air. The plane leaves Louisville International Airport-Standiford Field at 22:29 America/New_York. The flight is expected to land at Kansas City International Airport at None America/Chicago. The flight will last about 1 hours 36 minutes.

7Z9507 - EZR9507 EZ Air (7Z)
SDF Louisville United States
Flight SDF to MCI
MCI Kansas City United States
Contact Airlines It may not operate on the date requested
Departure Louisville International Airport-Standiford Field
IATA: SDFICAO: KSDF
Scheduled 22:29
None None
Arrival Kansas City International Airport
IATA: MCIICAO: KMCI
Scheduled None
None None
7Z9507 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 36 minutes
  • Flight Distance: 791 kms / 491 miles
Airline
  • EZ Air
  • IATA: 7Z
  • ICAO: EZR
  • Operating Days: Monday, Wednesday, Thursday, Friday, Saturday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: McDonnell Douglas DC-9-15RC
  • Callsign: AJI9507
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Chicago
  • Current Time in Louisville: Tuesday 2026-05-05 01:27 AM
  • Current Time in Kansas City: Tuesday 2026-05-05 00:27 AM

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EZ Air Flight 7Z9507 FAQs

What is the scheduled flight duration for EZ Air 7Z9507 flight?

On average, nonstop flight takes 1 hour(s) 36 minutes, with the flight distance of 791 km (491 miles).

What type of aircraft is used for the EZ Air 7Z9507 flight?

All EZ Air 7Z9507 flights are operated using McDonnell Douglas DC-9-15RC aircraft.

How many EZ Air 7Z9507 flights are operated a week?

6 flights per week. The Flight EZ Air 7Z9507 is operated on Monday, Wednesday, Thursday, Friday, Saturday, Sunday.