Delta DL5674 Flight Status : Live Tracking & Updates

Domestic flight Delta DL5674 takes off from Cleveland (CLE) United States to Boston (BOS) United States. It's operated by Delta Airlines. The plane leaves Cleveland Hopkins International Airport at 11:14 America/New_York. The flight is expected to land at Logan International Airport at 13:10 America/New_York. The flight will last about 1 hours 56 minutes.

DL5674 - DAL5674 Delta Airlines (DL)
CLE Cleveland United States
Flight CLE to BOS
BOS Boston United States
Contact Airlines It may not operate on the date requested
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 11:14
TERM B5
Arrival Logan International Airport
IATA: BOSICAO: KBOS
Scheduled 13:10
A A5
DL5674 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 56 minutes
  • Flight Distance: 903 kms / 561 miles
Airline
  • Delta Airlines
  • IATA: DL
  • ICAO: DAL
  • Operating Days: Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer 175
  • Callsign: T-KLGA56
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Cleveland: Monday 2026-05-25 20:10 PM
  • Current Time in Boston: Monday 2026-05-25 20:10 PM

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Delta Flight DL5674 FAQs

What is the scheduled flight duration for Delta DL5674 flight?

On average, nonstop flight takes 1 hour(s) 56 minutes, with the flight distance of 903 km (561 miles).

What type of aircraft is used for the Delta DL5674 flight?

All Delta DL5674 flights are operated using Embraer 175 aircraft.

Which terminal the flight Delta DL5674 is arriving at?

Flight Delta DL5674 arrives in Logan International Airport at Terminal A.

How many Delta DL5674 flights are operated a week?

1 flights per week. The Flight Delta DL5674 is operated on Sunday.