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Amapola HP6095 Flight Status : Live Tracking & Updates
Domestic flight Amapola HP6095 takes off from Columbus (CMH) United States to Houston (IAH) United States. It's operated by Amapola. The plane leaves John Glenn Columbus International Airport at 09:00 America/New_York. The flight is expected to land at George Bush Intercontinental Airport at 10:46 America/Chicago. The flight will last about 2 hours 46 minutes.
HP6095 - APF6095
Amapola (HP)
CMH
Columbus United States
IAH
Houston United States
NO FLIGHTS IN THE LAST 14 DAYS
Lasted record on
HP6095 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 46 minutes
- Flight Distance: 1587 kms / 986 miles
Airline
- Amapola
- IATA: HP
- ICAO: APF
- Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: None
- Callsign: None
- Departure Timezone: America/New_York
- Arrival Timezone: America/Chicago
- Current Time in Columbus: Monday 2026-05-25 02:58 AM
- Current Time in Houston: Monday 2026-05-25 01:58 AM
Flight routes similar to Amapola HP6095
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|---|---|---|---|
|
NZ9759 Air New Zealand |
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|
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|
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|
NZ9761 Air New Zealand |
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|
UA6283 United Airlines |
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|
NZ9757 Air New Zealand |
25/05/2026 06:05 |
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|
YV6287 Mesa Airlines |
25/05/2026 11:44 |
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Amapola Flight HP6095 FAQs
What is the scheduled flight duration for Amapola HP6095 flight?
On average, nonstop flight takes 2 hour(s) 46 minutes, with the flight distance of 1587 km (986 miles).
