Allegiant Air G45769 Flight Status : Live Tracking & Updates

Domestic flight Allegiant Air G45769 takes off from Saint Petersburg (PIE) United States to Bloomington (BMI) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 13:15 America/New_York. The flight is expected to land at Central Illinois Regional Airport at 14:36 America/Chicago. The flight will last about 2 hours 9 minutes.

G45769 - AAY5769 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to BMI
BMI Bloomington United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 03-August-2021
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 13:15
None None
Arrival Central Illinois Regional Airport
IATA: BMIICAO: KBMI
Scheduled 14:36
None None
G45769 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 9 minutes
  • Flight Distance: 1507 kms / 936 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Chicago
  • Current Time in Saint Petersburg: Wednesday 2026-05-06 17:43 PM
  • Current Time in Bloomington: Wednesday 2026-05-06 16:43 PM

Flight routes similar to Allegiant Air G45769

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Allegiant Air Flight G45769 FAQs

What is the scheduled flight duration for Allegiant Air G45769 flight?

On average, nonstop flight takes 2 hour(s) 9 minutes, with the flight distance of 1507 km (936 miles).