Allegiant Air G45491 Flight Status : Live Tracking & Updates

Domestic flight Allegiant Air G45491 takes off from Saint Petersburg (PIE) United States to Knoxville (TYS) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 11:00 America/New_York. The flight is expected to land at McGhee Tyson Airport at 12:33 America/New_York. The flight will last about 1 hours 22 minutes.

G45491 - AAY5491 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to TYS
TYS Knoxville United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 03-August-2021
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 11:00
None None
Arrival McGhee Tyson Airport
IATA: TYSICAO: KTYS
Scheduled 12:33
None None
G45491 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 22 minutes
  • Flight Distance: 884 kms / 549 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Saint Petersburg: Monday 2026-05-25 12:20 PM
  • Current Time in Knoxville: Monday 2026-05-25 12:20 PM

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Allegiant Air Flight G45491 FAQs

What is the scheduled flight duration for Allegiant Air G45491 flight?

On average, nonstop flight takes 1 hour(s) 22 minutes, with the flight distance of 884 km (549 miles).