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Allegiant Air G43027 Flight Status : Live Tracking & Updates
Domestic flight Allegiant Air G43027 takes off from Middletown (MDT) United States to Jacksonville (JAX) United States. It's operated by Allegiant Air. The plane leaves Harrisburg International Airport at 17:43 America/New_York. The flight is expected to land at Jacksonville International Airport at 19:49 America/New_York. The flight will last about 2 hours 6 minutes.
G43027 - AAY3027
Allegiant Air (G4)
MDT
Middletown United States
JAX
Jacksonville United States
Contact Airlines
It may not operate on the date requested
G43027 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 6 minutes
- Flight Distance: 1166 kms / 724 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Thursday, Saturday, Sunday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Airbus A320 (sharklets)
- Callsign: F-KPRX1
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Middletown: Tuesday 2026-05-05 04:27 AM
- Current Time in Jacksonville: Tuesday 2026-05-05 04:27 AM
Flight routes similar to Allegiant Air G43027
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
G41434 Allegiant Air |
05/05/2026 17:43 |
2 hours 6 minutes 19:49 |
Allegiant Air Flight G43027 FAQs
What is the scheduled flight duration for Allegiant Air G43027 flight?
On average, nonstop flight takes 2 hour(s) 6 minutes, with the flight distance of 1166 km (724 miles).
What type of aircraft is used for the Allegiant Air G43027 flight?
All Allegiant Air G43027 flights are operated using Airbus A320 (sharklets) aircraft.
How many Allegiant Air G43027 flights are operated a week?
3 flights per week. The Flight Allegiant Air G43027 is operated on Thursday, Saturday, Sunday.