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Allegiant Air G42708 Flight Status : Live Tracking & Updates
Domestic flight Allegiant Air G42708 takes off from Saint Petersburg (PIE) United States to Clarksburg (CKB) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 21:23 25 May 2026 America/New_York. The flight is expected to land at Benedum Airport at 23:38 25 May 2026 America/New_York. The flight will last about 2 hours 15 minutes.
Current status of G42708 is Scheduled On time Expected Depart in 7 hours, 34 minutes
- Type: Domestic Flight
- Flight Duration: 2 hours 15 minutes
- Flight Distance: 1283 kms / 797 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Tuesday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Boeing 737MAX 8 Passenger
- Callsign: T-KFWA1
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Saint Petersburg: Monday 2026-05-25 13:49 PM
- Current Time in Clarksburg: Monday 2026-05-25 13:49 PM
Allegiant Air Flight G42708 FAQs
What is the scheduled flight duration for Allegiant Air G42708 flight?
On average, nonstop flight takes 2 hour(s) 15 minutes, with the flight distance of 1283 km (797 miles).
What is the current status of Allegiant Air G42708 flight?
The current status of flight Allegiant Air G42708 is Scheduled On time.
What type of aircraft is used for the Allegiant Air G42708 flight?
All Allegiant Air G42708 flights are operated using Boeing 737MAX 8 Passenger aircraft.
How many Allegiant Air G42708 flights are operated a week?
1 flights per week. The Flight Allegiant Air G42708 is operated on Tuesday.
