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Allegiant Air G42708 Flight Status : Live Tracking & Updates
Domestic flight Allegiant Air G42708 takes off from Saint Petersburg (PIE) United States to Clarksburg (CKB) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 18:07 04 May 2026 America/New_York. The flight is expected to land at Benedum Airport at 20:19 04 May 2026 America/New_York. The flight will last about 2 hours 12 minutes.
Current status of G42708 is Arrived On time
- Type: Domestic Flight
- Flight Duration: 2 hours 12 minutes
- Flight Distance: 1283 kms / 797 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Tuesday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Airbus A319
- Callsign: T-KFWA1
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Saint Petersburg: Monday 2026-05-04 23:47 PM
- Current Time in Clarksburg: Monday 2026-05-04 23:47 PM
Flight routes similar to Allegiant Air G42708
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
G4984 Allegiant Air |
04/05/2026 18:23 |
2 hours 10 minutes 20:33 |
Allegiant Air Flight G42708 FAQs
What is the scheduled flight duration for Allegiant Air G42708 flight?
On average, nonstop flight takes 2 hour(s) 12 minutes, with the flight distance of 1283 km (797 miles).
What is the current status of Allegiant Air G42708 flight?
The current status of flight Allegiant Air G42708 is Arrived On time.
What type of aircraft is used for the Allegiant Air G42708 flight?
All Allegiant Air G42708 flights are operated using Airbus A319 aircraft.
How many Allegiant Air G42708 flights are operated a week?
1 flights per week. The Flight Allegiant Air G42708 is operated on Tuesday.
