Allegiant Air G4248 Flight Status : Live Tracking & Updates

Domestic flight Allegiant Air G4248 takes off from Asheville (AVL) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Asheville Regional Airport at 18:23 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 20:01 America/New_York. The flight will last about 1 hours 38 minutes.

G4248 - AAY248 Allegiant Air (G4)
AVL Asheville United States
Flight AVL to PIE
PIE Saint Petersburg United States
Contact Airlines It may not operate on the date requested
Departure Asheville Regional Airport
IATA: AVLICAO: KAVL
Scheduled 18:23
None None
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 20:01
None 9
G4248 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 38 minutes
  • Flight Distance: 834 kms / 518 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Thursday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: F-KEWR1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Asheville: Monday 2026-05-25 09:55 AM
  • Current Time in Saint Petersburg: Monday 2026-05-25 09:55 AM

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Allegiant Air Flight G4248 FAQs

What is the scheduled flight duration for Allegiant Air G4248 flight?

On average, nonstop flight takes 1 hour(s) 38 minutes, with the flight distance of 834 km (518 miles).

What type of aircraft is used for the Allegiant Air G4248 flight?

All Allegiant Air G4248 flights are operated using Airbus A320 aircraft.

How many Allegiant Air G4248 flights are operated a week?

2 flights per week. The Flight Allegiant Air G4248 is operated on Thursday, Sunday.