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Allegiant Air G41078 Flight Status : Live Tracking & Updates
Domestic flight Allegiant Air G41078 takes off from Saint Petersburg (PIE) United States to Middletown (MDT) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 16:54 America/New_York. The flight is expected to land at Harrisburg International Airport at 19:17 America/New_York. The flight will last about 2 hours 23 minutes.
G41078 - AAY1078
Allegiant Air (G4)
PIE
Saint Petersburg United States
MDT
Middletown United States
Contact Airlines
It may not operate on the date requested
Scheduled
16:54
None
4
G41078 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 23 minutes
- Flight Distance: 1468 kms / 912 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Monday, Friday, Saturday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Boeing 737MAX 8 Passenger
- Callsign: F-KATL3
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Saint Petersburg: Thursday 2026-05-07 17:24 PM
- Current Time in Middletown: Thursday 2026-05-07 17:24 PM
Flight routes similar to Allegiant Air G41078
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
G43678 Allegiant Air |
07/05/2026 None |
19:30 |
Allegiant Air Flight G41078 FAQs
What is the scheduled flight duration for Allegiant Air G41078 flight?
On average, nonstop flight takes 2 hour(s) 23 minutes, with the flight distance of 1468 km (912 miles).
What type of aircraft is used for the Allegiant Air G41078 flight?
All Allegiant Air G41078 flights are operated using Boeing 737MAX 8 Passenger aircraft.
How many Allegiant Air G41078 flights are operated a week?
3 flights per week. The Flight Allegiant Air G41078 is operated on Monday, Friday, Saturday.