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Allegiant Air G41046 Flight Status : Live Tracking & Updates
Domestic flight Allegiant Air G41046 takes off from Akron (CAK) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Akron-Canton Airport at 07:00 25 May 2026 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 09:23 25 May 2026 America/New_York. The flight will last about 2 hours 13 minutes.
Current status of G41046 is Arrived On time
- Type: Domestic Flight
- Flight Duration: 2 hours 13 minutes
- Flight Distance: 1447 kms / 899 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Sunday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Boeing 737MAX 8 Passenger
- Callsign: F-KDBQ3
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Akron: Monday 2026-05-25 20:40 PM
- Current Time in Saint Petersburg: Monday 2026-05-25 20:40 PM
Flight routes similar to Allegiant Air G41046
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
G4971 Allegiant Air |
25/05/2026 21:06 |
2 hours 22 minutes 23:28 |
Allegiant Air Flight G41046 FAQs
What is the scheduled flight duration for Allegiant Air G41046 flight?
On average, nonstop flight takes 2 hour(s) 13 minutes, with the flight distance of 1447 km (899 miles).
What is the current status of Allegiant Air G41046 flight?
The current status of flight Allegiant Air G41046 is Arrived On time.
What type of aircraft is used for the Allegiant Air G41046 flight?
All Allegiant Air G41046 flights are operated using Boeing 737MAX 8 Passenger aircraft.
How many Allegiant Air G41046 flights are operated a week?
1 flights per week. The Flight Allegiant Air G41046 is operated on Sunday.
