Allegiant Air G41046 Flight Status : Live Tracking & Updates

Domestic flight Allegiant Air G41046 takes off from Akron (CAK) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Akron-Canton Airport at 12:10 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 14:33 America/New_York. The flight will last about 2 hours 23 minutes.

G41046 - AAY1046 Allegiant Air (G4)
CAK Akron United States
Flight CAK to PIE
PIE Saint Petersburg United States
Contact Airlines It may not operate on the date requested
Departure Akron-Canton Airport
IATA: CAKICAO: KCAK
Scheduled 12:10
None None
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 14:33
None 8
G41046 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 23 minutes
  • Flight Distance: 1447 kms / 899 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: F-KDBQ3
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Akron: Tuesday 2026-05-05 12:42 PM
  • Current Time in Saint Petersburg: Tuesday 2026-05-05 12:42 PM

Allegiant Air Flight G41046 FAQs

What is the scheduled flight duration for Allegiant Air G41046 flight?

On average, nonstop flight takes 2 hour(s) 23 minutes, with the flight distance of 1447 km (899 miles).

What type of aircraft is used for the Allegiant Air G41046 flight?

All Allegiant Air G41046 flights are operated using Airbus A320 aircraft.

How many Allegiant Air G41046 flights are operated a week?

1 flights per week. The Flight Allegiant Air G41046 is operated on Sunday.