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Allegiant Air G41014 Flight Status : Live Tracking & Updates
Domestic flight Allegiant Air G41014 takes off from Saint Petersburg (PIE) United States to Cedar Rapids (CID) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 15:22 America/New_York. The flight is expected to land at The Eastern Iowa Airport at 17:16 America/Chicago. The flight will last about 2 hours 54 minutes.
G41014 - AAY1014
Allegiant Air (G4)
PIE
Saint Petersburg United States
CID
Cedar Rapids United States
Contact Airlines
It may not operate on the date requested
Scheduled
15:22
None
3
G41014 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 54 minutes
- Flight Distance: 1753 kms / 1089 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Monday, Friday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Airbus A319
- Callsign: F-KMRC3
- Departure Timezone: America/New_York
- Arrival Timezone: America/Chicago
- Current Time in Saint Petersburg: Tuesday 2026-05-05 12:34 PM
- Current Time in Cedar Rapids: Tuesday 2026-05-05 11:34 AM
Flight routes similar to Allegiant Air G41014
Allegiant Air Flight G41014 FAQs
What is the scheduled flight duration for Allegiant Air G41014 flight?
On average, nonstop flight takes 2 hour(s) 54 minutes, with the flight distance of 1753 km (1089 miles).
What type of aircraft is used for the Allegiant Air G41014 flight?
All Allegiant Air G41014 flights are operated using Airbus A319 aircraft.
How many Allegiant Air G41014 flights are operated a week?
2 flights per week. The Flight Allegiant Air G41014 is operated on Monday, Friday.
