Alitalia AZ5735 Flight Status : Live Tracking & Updates

International flight Alitalia AZ5735 takes off from Abu Dhabi (AUH) United Arab Emirates to Mahe Island (SEZ) Seychelles. It's operated by Alitalia. The plane leaves Abu Dhabi International Airport at 01:15 Asia/Dubai. The flight is expected to land at Seychelles International Airport at 05:50 Indian/Mahe. The flight will last about 4 hours 35 minutes.

AZ5735 - AZA5735 Alitalia (AZ)
AUH Abu Dhabi United Arab Emirates
Flight AUH to SEZ
SEZ Mahe Island Seychelles
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 14-October-2021
Departure Abu Dhabi International Airport
IATA: AUHICAO: OMAA
Scheduled 01:15
3 None
Arrival Seychelles International Airport
IATA: SEZICAO: FSIA
Scheduled 05:50
I None
AZ5735 Detail
  • Type: International Flight
  • Flight Duration: 4 hours 35 minutes
  • Flight Distance: 3220 kms / 2001 miles
Airline
  • Alitalia
  • IATA: AZ
  • ICAO: AZA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 136
  • Freight capacity: 0 tons
  • Passenger classes: Economy, Business Class, Shuttle
More Detail
  • Aircraft: Airbus A320 (sharklets)
  • Callsign: AZA5735
  • Departure Timezone: Asia/Dubai
  • Arrival Timezone: Indian/Mahe
  • Current Time in Abu Dhabi: Friday 2026-05-08 05:03 AM
  • Current Time in Mahe Island: Friday 2026-05-08 05:03 AM

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Alitalia Flight AZ5735 FAQs

What is the scheduled flight duration for Alitalia AZ5735 flight?

On average, nonstop flight takes 4 hour(s) 35 minutes, with the flight distance of 3220 km (2001 miles).

What type of aircraft is used for the Alitalia AZ5735 flight?

All Alitalia AZ5735 flights are operated using Airbus A320 (sharklets) aircraft.

Which terminal the flight Alitalia AZ5735 is arriving at?

Flight Alitalia AZ5735 arrives in Seychelles International Airport at Terminal I.