Alitalia AZ2058 Flight Status : Live Tracking & Updates

Domestic flight Alitalia AZ2058 takes off from Rome (FCO) Italy to Milan (LIN) Italy. It's operated by Alitalia. The plane leaves Leonardo da Vinci-Fiumicino Airport at 21:00 Europe/Rome. The flight is expected to land at Milano Linate Airport at 22:10 Europe/Rome. The flight will last about 1 hours 10 minutes.

AZ2058 - AZA2058 Alitalia (AZ)
FCO Rome Italy
Flight FCO to LIN
LIN Milan Italy
Contact Airlines It may not operate on the date requested
Departure Leonardo da Vinci-Fiumicino Airport
IATA: FCOICAO: LIRF
Scheduled 21:00
1 None
Arrival Milano Linate Airport
IATA: LINICAO: LIML
Scheduled 22:10
None None
AZ2058 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 10 minutes
  • Flight Distance: 473 kms / 294 miles
Airline
  • Alitalia
  • IATA: AZ
  • ICAO: AZA
  • Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday
Passenger Services
  • Service type: Normal passenger
  • Seats: 144
  • Freight capacity: 6.7 tons
  • Passenger classes: Economy, Business Class, Shuttle
More Detail
  • Aircraft: Airbus A220-300 Passenger
  • Callsign: AZA2058
  • Departure Timezone: Europe/Rome
  • Arrival Timezone: Europe/Rome
  • Current Time in Rome: Tuesday 2026-05-05 10:57 AM
  • Current Time in Milan: Tuesday 2026-05-05 10:57 AM

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Alitalia Flight AZ2058 FAQs

What is the scheduled flight duration for Alitalia AZ2058 flight?

On average, nonstop flight takes 1 hour(s) 10 minutes, with the flight distance of 473 km (294 miles).

What type of aircraft is used for the Alitalia AZ2058 flight?

All Alitalia AZ2058 flights are operated using Airbus A220-300 Passenger aircraft.

How many Alitalia AZ2058 flights are operated a week?

6 flights per week. The Flight Alitalia AZ2058 is operated on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday.