Air India AI1788 Flight Status : Live Tracking & Updates

Domestic flight Air India AI1788 takes off from Port Blair (IXZ) India to Kolkata (CCU) India. It's operated by Air India. The plane leaves Port Blair Airport at 09:50 Asia/Kolkata. The flight is expected to land at Netaji Subhas Chandra Bose Airport at 12:00 Asia/Kolkata. The flight will last about 2 hours 20 minutes.

AI1788 - AIC1788 Air India (AI)
IXZ Port Blair India
Flight IXZ to CCU
CCU Kolkata India
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 16-August-2020
Departure Port Blair Airport
IATA: IXZICAO: VOPB
Scheduled 09:50
Arrival Netaji Subhas Chandra Bose Airport
IATA: CCUICAO: VECC
Scheduled 12:00
AI1788 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 20 minutes
  • Flight Distance: 1299 kms / 807 miles
Airline
  • Air India
  • IATA: AI
  • ICAO: AIC
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft:
  • Callsign: None
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Port Blair: Thursday 2026-05-07 21:03 PM
  • Current Time in Kolkata: Thursday 2026-05-07 21:03 PM

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Air India Flight AI1788 FAQs

What is the scheduled flight duration for Air India AI1788 flight?

On average, nonstop flight takes 2 hour(s) 20 minutes, with the flight distance of 1299 km (807 miles).