Air India Express IX2538 Flight Status : Live Tracking & Updates

Domestic flight Air India Express IX2538 takes off from Kolkata (CCU) India to Bengaluru (BLR) India. It's operated by Air India Express. The plane leaves Netaji Subhas Chandra Bose Airport at 15:05 Asia/Kolkata. The flight is expected to land at Kempegowda International Airport at 17:55 Asia/Kolkata. The flight will last about 2 hours 40 minutes.

IX2538 - AXB2538 Air India Express (IX)
CCU Kolkata India
Flight CCU to BLR
BLR Bengaluru India
Contact Airlines It may not operate on the date requested
Departure Netaji Subhas Chandra Bose Airport
IATA: CCUICAO: VECC
Scheduled 15:05
None None
Arrival Kempegowda International Airport
IATA: BLRICAO: VOBL
Scheduled 17:55
2 D9
IX2538 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 40 minutes
  • Flight Distance: 1543 kms / 959 miles
Airline
  • Air India Express
  • IATA: IX
  • ICAO: AXB
  • Operating Days:
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320neo
  • Callsign: AXB2538
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Kolkata: Tuesday 2026-05-05 07:08 AM
  • Current Time in Bengaluru: Tuesday 2026-05-05 07:08 AM

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Air India Express Flight IX2538 FAQs

What is the scheduled flight duration for Air India Express IX2538 flight?

On average, nonstop flight takes 2 hour(s) 40 minutes, with the flight distance of 1543 km (959 miles).

What type of aircraft is used for the Air India Express IX2538 flight?

All Air India Express IX2538 flights are operated using Airbus A320neo aircraft.

Which terminal the flight Air India Express IX2538 is arriving at?

Flight Air India Express IX2538 arrives in Kempegowda International Airport at Terminal 2.