Air Canada AC6866 Flight Status : Live Tracking & Updates

Domestic flight Air Canada AC6866 takes off from Johannesburg (JNB) South Africa to Port Elizabeth (PLZ) South Africa. It's operated by Air Canada. The plane leaves O.R. Tambo International Airport at 10:55 Africa/Johannesburg. The flight is expected to land at Port Elizabeth International Airport at 12:30 Africa/Johannesburg. The flight will last about 1 hours 35 minutes.

AC6866 - ACA6866 Air Canada (AC)
JNB Johannesburg South Africa
Flight JNB to PLZ
PLZ Port Elizabeth South Africa
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 28-February-2020
Departure O.R. Tambo International Airport
IATA: JNBICAO: FAOR
Scheduled 10:55
B None
Arrival Port Elizabeth International Airport
IATA: PLZICAO: FAPE
Scheduled 12:30
None None
AC6866 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 35 minutes
  • Flight Distance: 906 kms / 563 miles
Airline
  • Air Canada
  • IATA: AC
  • ICAO: ACA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 145
  • Freight capacity: 9.4 tons
  • Passenger classes: First Class, Economy, Business Class, Shuttle
More Detail
  • Aircraft: Airbus A320
  • Callsign: ACA6866
  • Departure Timezone: Africa/Johannesburg
  • Arrival Timezone: Africa/Johannesburg
  • Current Time in Johannesburg: Monday 2026-05-04 16:35 PM
  • Current Time in Port Elizabeth: Monday 2026-05-04 16:35 PM

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Air Canada Flight AC6866 FAQs

What is the scheduled flight duration for Air Canada AC6866 flight?

On average, nonstop flight takes 1 hour(s) 35 minutes, with the flight distance of 906 km (563 miles).

What type of aircraft is used for the Air Canada AC6866 flight?

All Air Canada AC6866 flights are operated using Airbus A320 aircraft.