Air India AI9403 Flight Status Today

Domestic flight Air India AI9403 takes off from Dibrugarh (DIB) India to Kolkata (CCU) India. It's operated by Air India. The plane leaves Dibrugarh Airport at 16:00 Asia/Kolkata. The flight is expected to land at Netaji Subhas Chandra Bose Airport at 17:30 Asia/Kolkata. The flight will last about 1 hours 30 minutes.

AI9403 - AIC9403 Air India (AI)
DIB Dibrugarh India
Flight DIB to CCU
CCU Kolkata India
Contact Airlines It may not operate on the date requested
Departure Dibrugarh Airport
IATA: DIBICAO: VEMN
Scheduled 16:00
None None
Arrival Netaji Subhas Chandra Bose Airport
IATA: CCUICAO: VECC
Scheduled 17:30
None None
AI9403 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 30 minutes
  • Flight Distance: 853 kms / 530 miles
Airline
  • Air India
  • IATA: AI
  • ICAO: AIC
  • Operating Days: Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320 (sharklets)
  • Callsign: None
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Dibrugarh: Monday 2025-12-29 21:40 PM
  • Current Time in Kolkata: Monday 2025-12-29 21:40 PM

Flight routes similar to Air India AI9403

Airline Flight no Departure Arrival
IndiGo 6E6894
IndiGo 		29/12/2025
11:45 		2 hours 2 minutes
13:40
IndiGo 6E6102
IndiGo 		29/12/2025
16:15 		1 hours 50 minutes
18:05

Air India Flight AI9403 FAQs

What is the scheduled flight duration for Air India AI9403 flight?

On average, nonstop flight takes 1 hour(s) 30 minutes, with the flight distance of 853 km (530 miles).

What type of aircraft is used for the Air India AI9403 flight?

All Air India AI9403 flights are operated using Airbus A320 (sharklets) aircraft.

How many Air India AI9403 flights are operated a week?

1 flights per week. The Flight Air India AI9403 is operated on Sunday.