Aeromexico AM9480 Flight Status : Live Tracking & Updates

Domestic flight Aeromexico AM9480 takes off from Mexico City (MEX) Mexico to Acapulco (ACA) Mexico. It's operated by Aeromexico. The plane leaves Benito Juarez International Airport at 12:05 America/Mexico_City. The flight is expected to land at Acapulco International Airport at 13:15 America/Mexico_City. The flight will last about 1 hours 10 minutes.

AM9480 - AMX9480 Aeromexico (AM)
MEX Mexico City Mexico
Flight MEX to ACA
ACA Acapulco Mexico
Contact Airlines It may not operate on the date requested
Departure Benito Juarez International Airport
IATA: MEXICAO: MMMX
Scheduled 12:05
None None
Arrival Acapulco International Airport
IATA: ACAICAO: MMAA
Scheduled 13:15
None None
AM9480 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 10 minutes
  • Flight Distance: 305 kms / 189 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: Monday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: F-KGSB1
  • Departure Timezone: America/Mexico_City
  • Arrival Timezone: America/Mexico_City
  • Current Time in Mexico City: Thursday 2026-05-07 21:05 PM
  • Current Time in Acapulco: Thursday 2026-05-07 21:05 PM

Flight routes similar to Aeromexico AM9480

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Delta DL8025
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Iberia IB9027
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KLM KL9032
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Japan Airlines JL8228
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Delta DL8017
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Aeromexico Flight AM9480 FAQs

What is the scheduled flight duration for Aeromexico AM9480 flight?

On average, nonstop flight takes 1 hour(s) 10 minutes, with the flight distance of 305 km (189 miles).

What type of aircraft is used for the Aeromexico AM9480 flight?

All Aeromexico AM9480 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Aeromexico AM9480 flights are operated a week?

1 flights per week. The Flight Aeromexico AM9480 is operated on Monday.