Aeromexico AM7480 Flight Status : Live Tracking & Updates

Domestic flight Aeromexico AM7480 takes off from Buenos Aires (AEP) Argentina to Tucuman (TUC) Argentina. It's operated by Aeromexico. The plane leaves Jorge Newbery Airport at 09:35 America/Argentina/Buenos_Aires. The flight is expected to land at Teniente Benjamin Matienzo Airport at 11:35 America/Argentina/Buenos_Aires. The flight will last about 1 hours 52 minutes.

AM7480 - AMX7480 Aeromexico (AM)
AEP Buenos Aires Argentina
Flight AEP to TUC
TUC Tucuman Argentina
Contact Airlines It may not operate on the date requested
Departure Jorge Newbery Airport
IATA: AEPICAO: SABE
Scheduled 09:35
TA 13
Arrival Teniente Benjamin Matienzo Airport
IATA: TUCICAO: SANT
Scheduled 11:35
None None
AM7480 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 52 minutes
  • Flight Distance: 1069 kms / 664 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: Monday, Tuesday, Thursday, Friday, Saturday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: None
  • Departure Timezone: America/Argentina/Buenos_Aires
  • Arrival Timezone: America/Argentina/Buenos_Aires
  • Current Time in Buenos Aires: Thursday 2026-05-07 05:40 AM
  • Current Time in Tucuman: Thursday 2026-05-07 05:40 AM

Flight routes similar to Aeromexico AM7480

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Aeromexico Flight AM7480 FAQs

What is the scheduled flight duration for Aeromexico AM7480 flight?

On average, nonstop flight takes 1 hour(s) 52 minutes, with the flight distance of 1069 km (664 miles).

What type of aircraft is used for the Aeromexico AM7480 flight?

All Aeromexico AM7480 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Aeromexico AM7480 flights are operated a week?

6 flights per week. The Flight Aeromexico AM7480 is operated on Monday, Tuesday, Thursday, Friday, Saturday, Sunday.