Air Canada AC7478 Flight Status Today

International flight Air Canada AC7478 takes off from Toronto (YYZ) Canada to Newark (EWR) United States. It's operated by Air Canada. The plane leaves Pearson International Airport at 16:00 America/Toronto. The flight is expected to land at Newark Liberty International Airport at 17:31 America/New_York. The flight will last about 1 hours 31 minutes.

AC7478 - ACA7478 Air Canada (AC)
YYZ Toronto Canada
Flight YYZ to EWR
EWR Newark United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 09-January-2022
Departure Pearson International Airport
IATA: YYZICAO: CYYZ
Scheduled 16:00
1 None
Arrival Newark Liberty International Airport
IATA: EWRICAO: KEWR
Scheduled 17:31
A None
AC7478 Detail
  • Type: International Flight
  • Flight Duration: 1 hours 31 minutes
  • Flight Distance: 558 kms / 347 miles
Airline
  • Air Canada
  • IATA: AC
  • ICAO: ACA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 73
  • Freight capacity: 1.2 tons
  • Passenger classes: First Class, Economy, Business Class, Shuttle
More Detail
  • Aircraft: Embraer 175
  • Callsign: ACA7478
  • Departure Timezone: America/Toronto
  • Arrival Timezone: America/New_York
  • Current Time in Toronto: Thursday 2026-01-01 06:33 AM
  • Current Time in Newark: Thursday 2026-01-01 06:33 AM

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Air Canada Flight AC7478 FAQs

What is the scheduled flight duration for Air Canada AC7478 flight?

On average, nonstop flight takes 1 hour(s) 31 minutes, with the flight distance of 558 km (347 miles).

What type of aircraft is used for the Air Canada AC7478 flight?

All Air Canada AC7478 flights are operated using Embraer 175 aircraft.

Which terminal the flight Air Canada AC7478 is arriving at?

Flight Air Canada AC7478 arrives in Newark Liberty International Airport at Terminal A.