Air Canada AC7474 Flight Status Today

International flight Air Canada AC7474 takes off from Toronto (YYZ) Canada to Newark (EWR) United States. It's operated by Air Canada. The plane leaves Pearson International Airport at 11:55 America/Toronto. The flight is expected to land at Newark Liberty International Airport at 13:25 America/New_York. The flight will last about 1 hours 41 minutes.

AC7474 - ACA7474 Air Canada (AC)
YYZ Toronto Canada
Flight YYZ to EWR
EWR Newark United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 30-April-2022
Departure Pearson International Airport
IATA: YYZICAO: CYYZ
Scheduled 11:55
1 None
Arrival Newark Liberty International Airport
IATA: EWRICAO: KEWR
Scheduled 13:25
A None
AC7474 Detail
  • Type: International Flight
  • Flight Duration: 1 hours 41 minutes
  • Flight Distance: 558 kms / 347 miles
Airline
  • Air Canada
  • IATA: AC
  • ICAO: ACA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 73
  • Freight capacity: 1.2 tons
  • Passenger classes: First Class, Economy, Business Class, Shuttle
More Detail
  • Aircraft: Embraer 175
  • Callsign: ACA7474
  • Departure Timezone: America/Toronto
  • Arrival Timezone: America/New_York
  • Current Time in Toronto: Thursday 2026-01-01 06:33 AM
  • Current Time in Newark: Thursday 2026-01-01 06:33 AM

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Air Canada Flight AC7474 FAQs

What is the scheduled flight duration for Air Canada AC7474 flight?

On average, nonstop flight takes 1 hour(s) 41 minutes, with the flight distance of 558 km (347 miles).

What type of aircraft is used for the Air Canada AC7474 flight?

All Air Canada AC7474 flights are operated using Embraer 175 aircraft.

Which terminal the flight Air Canada AC7474 is arriving at?

Flight Air Canada AC7474 arrives in Newark Liberty International Airport at Terminal A.