WestJet WS4563 Flight Status : Live Tracking & Updates

Domestic flight WestJet WS4563 takes off from Calgary (YYC) Canada to Kelowna (YLW) Canada. It's operated by WestJet Airlines. The plane leaves Calgary International Airport at 16:20 America/Edmonton. The flight is expected to land at Kelowna International Airport at 16:30 America/Vancouver. The flight will last about 1 hours 10 minutes.

WS4563 - WJA4563 WestJet Airlines (WS)
YYC Calgary Canada
Flight YYC to YLW
YLW Kelowna Canada
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 30-April-2021
Departure Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 16:20
None B35
Arrival Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 16:30
None 8
WS4563 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 10 minutes
  • Flight Distance: 403 kms / 250 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: America/Edmonton
  • Arrival Timezone: America/Vancouver
  • Current Time in Calgary: Sunday 2026-05-24 12:03 PM
  • Current Time in Kelowna: Sunday 2026-05-24 11:03 AM

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WestJet Flight WS4563 FAQs

What is the scheduled flight duration for WestJet WS4563 flight?

On average, nonstop flight takes 1 hour(s) 10 minutes, with the flight distance of 403 km (250 miles).