Uzbekistan Airways HY7207 Flight Status : Live Tracking & Updates

Domestic flight Uzbekistan Airways HY7207 takes off from Rome (FCO) Italy to Venice (VCE) Italy. It's operated by Uzbekistan Airways. The plane leaves Leonardo da Vinci-Fiumicino Airport at 13:30 Europe/Rome. The flight is expected to land at Venice Marco Polo Airport at 14:40 Europe/Rome. The flight will last about 1 hours 1 minutes.

HY7207 - UZB7207 Uzbekistan Airways (HY)
FCO Rome Italy
Flight FCO to VCE
VCE Venice Italy
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 22-October-2020
Departure Leonardo da Vinci-Fiumicino Airport
IATA: FCOICAO: LIRF
Scheduled 13:30
1 B30
Arrival Venice Marco Polo Airport
IATA: VCEICAO: LIPZ
Scheduled 14:40
None None
HY7207 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 1 minutes
  • Flight Distance: 412 kms / 256 miles
Airline
  • Uzbekistan Airways
  • IATA: HY
  • ICAO: UZB
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft:
  • Callsign: None
  • Departure Timezone: Europe/Rome
  • Arrival Timezone: Europe/Rome
  • Current Time in Rome: Sunday 2026-05-24 22:39 PM
  • Current Time in Venice: Sunday 2026-05-24 22:39 PM

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Uzbekistan Airways Flight HY7207 FAQs

What is the scheduled flight duration for Uzbekistan Airways HY7207 flight?

On average, nonstop flight takes 1 hour(s) 1 minutes, with the flight distance of 412 km (256 miles).