Air Canada AC7105 Flight Status : Live Tracking & Updates

International flight Air Canada AC7105 takes off from Toronto (YYZ) Canada to Kingston (KIN) Jamaica. It's operated by Air Canada. The plane leaves Pearson International Airport at America/Toronto. The flight is expected to land at Norman Manley International Airport at 12:33 America/Jamaica. The flight will last about 4 hours 30 minutes.

AC7105 - ACA7105 Air Canada (AC)
YYZ Toronto Canada
Flight YYZ to KIN
KIN Kingston Jamaica
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Pearson International Airport
IATA: YYZICAO: CYYZ
Scheduled
Arrival Norman Manley International Airport
IATA: KINICAO: MKJP
Scheduled 12:33
AC7105 Detail
  • Type: International Flight
  • Flight Duration: 4 hours 30 minutes
  • Flight Distance: 2867 kms / 1781 miles
Airline
  • Air Canada
  • IATA: AC
  • ICAO: ACA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft:
  • Callsign: None
  • Departure Timezone: America/Toronto
  • Arrival Timezone: America/Jamaica
  • Current Time in Toronto: Sunday 2026-05-24 19:13 PM
  • Current Time in Kingston: Sunday 2026-05-24 18:13 PM

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Air Canada Flight AC7105 FAQs

What is the scheduled flight duration for Air Canada AC7105 flight?

On average, nonstop flight takes 4 hour(s) 30 minutes, with the flight distance of 2867 km (1781 miles).