Aeroflot SU3461 Flight Status : Live Tracking & Updates

Domestic flight Aeroflot SU3461 takes off from Jacksonville (JAX) United States to New York (JFK) United States. It's operated by Aeroflot. The plane leaves Jacksonville International Airport at 11:35 America/New_York. The flight is expected to land at John F. Kennedy International Airport at 13:52 America/New_York. The flight will last about 1 hours 46 minutes.

SU3461 - AFL3461 Aeroflot (SU)
JAX Jacksonville United States
Flight JAX to JFK
JFK New York United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 15-December-2020
Departure Jacksonville International Airport
IATA: JAXICAO: KJAX
Scheduled 11:35
MAIN
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 13:52
SU3461 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 46 minutes
  • Flight Distance: 1333 kms / 828 miles
Airline
  • Aeroflot
  • IATA: SU
  • ICAO: AFL
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 110
  • Freight capacity: 1 tons
  • Passenger classes: Economy, Business Class, Shuttle
More Detail
  • Aircraft: B712
  • Callsign: AFL3461
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Jacksonville: Sunday 2026-05-24 17:06 PM
  • Current Time in New York: Sunday 2026-05-24 17:06 PM

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Aeroflot Flight SU3461 FAQs

What is the scheduled flight duration for Aeroflot SU3461 flight?

On average, nonstop flight takes 1 hour(s) 46 minutes, with the flight distance of 1333 km (828 miles).

What type of aircraft is used for the Aeroflot SU3461 flight?

All Aeroflot SU3461 flights are operated using B712 aircraft.